จงหาค่า \(x\) ในสมการ \(\frac{12}{x^{2}}-\frac{14}{x^{3}}=\frac{30x^{2}+10x^{3}}{x^{5}}\)

วิธีทำ

\begin{array}{lcl}\frac{12}{x^{2}}-\frac{14}{x^{3}}&=&\frac{30x^{2}+10x^{3}}{x^{5}}\\\frac{12x^{3}-14x^{2}}{x^{5}}&=&\frac{30x^{2}+10x^{3}}{x^{5}}\\12x^{3}-14x^{2}&=&30x^{2}+10x^{3}\\12x^{3}-10x^{3}&=&30x^{2}+14x^{2}\\2x^{3}&=&44x^{2}\\x&=&22\end{array}